PSI - Issue 6
L.M. Kagan-Rosenzweig / Procedia Structural Integrity 6 (2017) 216–223 L.M. Kagan-Rosenzweig / Structural Integrity Procedia 00 (2017) 000–000
219
4
P P P −
M ∆ =
∆
.
(13)
M
2
1
c
Combining the above equations, we get the required formula:
/ P P P
0 0 0 0 w w w ∆ = − .
0
0 0 0 w a b x
= +
( ∆ + +
(14)
,
)
M M
−
1
c
In what follows the lower support is assumed to be immovable, that is 0 0 , a b of this formula are calculated from the boundary conditions, have the meaning of specific (divided by the force P ) support reactions at the lower end, arising due to deflection 0 w . For the cantilever rod it turns out that 0 1 0 a w = − , 0 0 = b . 0 0 0 = w and 0 0 w w ∆ = . Constants
0 0 = a ,
0 0 = b .
For the hinged rod
In these two cases Eq. (14) converts into known approximate formulas. When the rod is fixed at the bottom and hinged at its upper end, constants
0 0 , a b provide the zero moment and
deflection at the upper end. Applying the Maxwell-More formula, we obtain
l
l
0
2
− EI w x l x ( )(
− EI l x
)
(
)
0
0
0
0
0
a = −
=
lb
.
(15)
,
b
dx
dx
For the rod with fixed both ends, linear and angular deflections of the lower end with fixed upper one are equal zero, constants 0 0 , a b are the solution of the system
l
l
l
l
l
l
0
2 EI x
0
1
( )
( )
EI x
EI w x
EI x
EI xw x
0
0
0
0
0
0
0
0
0
0
⋅ dx a
+
⋅ dx b
+
=
⋅ dx a
+
⋅ dx b
+
=
,
.
(16)
0
0
dx
dx
EI
3. The rod compressed by a system of forces
The system of concentrated and distributed compressive forces is specified by the load parameter K . Concen trated forces i i P Kp = , n i 1,2..., = are applied in sections with coordinates i x x = ; ( ) ( ) Kr x R x = is distributed compressive force. 0 0 P Kp = is the vertical reaction at lower support. c K is the critical value of K . Let 0 w be the deflection in the absence of compressive load. We divide the rod into two pieces and calculate the moment ( ) 0 m Kf w = in the section of curved rod due to vertical load only. Such calculation of m does not provide
( ) 0 f w can be written in two different forms, depending we consider the upper or the
equilibrium, so the function
lower part of the rod:
x 0
n
i = 1
0
0
0
0
0
0
0
f w p w w ( ( ) =
) − −
p w w ( −
−
−
(17.1)
)
r y w x w y dy ( )] ( )[ ( )
0
0
i
i
x x i >
l
n
i = 1
0
0
0
0
0
=
p w w ( −
+
−
(17.2)
( )
)
r y w x w y dy ( )] ( )[ ( )
f w
i
i
x x i <
x
( ) 0 f w affects
Eq. (17.1) and (17.2) differ linearly with respect to x , so that the choice of particular expression for
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