PSI - Issue 32
Denis N. Sheydakov et al. / Procedia Structural Integrity 32 (2021) 313–320 Denis N. Sheydakov, Irina B. Mikhailova / Structural Integrity Procedia 00 (2021) 000 – 000
317
5
3. Perturbed state of circular rod We assume that in addition to the above-described state of equilibrium X for the micropolar rod with prestressed coating, there is an infinitely close equilibrium state p X under the same externalloads, which is determined by the radius-vectors , p p R R and the microrotation tensors , p p H H : , , , = , = , = , = p p p p R R Z Z R R Z Z R R Z Z R R Z Z v v v v v v R R v R R v H H H ω H H H ω v e e e v e e e ω e e e ω e e e where isasmallparameter; , v v are the vectors of additional displacements; , ω ω are the linear incremental rotation vectors, which characterizes the small rotation of themicropolar medium particles, measured from the deformed state X . The linearized equilibrium equationsfor the considered structure have the form(Eremeyev andZubov 1994):
= , D 0
T G v D C D 0 T = ,
0
r r
0
(12)
T
T
= , D 0
= , G v D C D 0
r r r
0
Here , G G are the linearized Piola-type stress and couple stress tensors for the rod and the coating. Bylinearizingtheconstitutiverelations (5), (8), the expressions for these tensors in the case of a physically linear micropolar material (4), (6) are obtained (Sheydakov et al. 2020). Linearizedboundaryconditionsonthesurfaceofthecoating = r r and at the interface between the coating and the rod 0 = r r are written as follows (Sheydakov2011): -T T , = ; det r r r pJ J e D e C v I v e G 0 C D D and ,
r r
r r
(13)
e D e D
e G e G
v v
,
,
,
ω ω
r
r
r
r
r r
r r
r r
r r
r r
r r
0
0
r r
r r
0
0
0
0
0
0
Here isthe nabla-operator in Eulerian coordinates. We assume that there is no friction at the ends of the considered composite structure l z = 0, , andconstant normal displacement is given. This leads to the following linearized endconditions(Sheydakovand Altenbach2016):
e D e
e D e
e G e
z e v
= e ω e ω
=
=
= 0,
=
= 0
z
R
z
z
Z
r
=0, z l
=0, z l
=0, z l
=0, z l
=0, z l
=0, z l
(14)
e D e
e D e
e G e
z e v
= e ω e ω
=
=
= 0,
=
= 0
z
R
z
z
Z
r
=0, z l
=0, z l
=0, z l
=0, z l
=0, z l
=0, z l
To solve the linearized boundaryvalue problem (12) – (14) for a system of twelve partial differential equations, the following substitution is used (Sheydakov 2011; Sheydakovand Altenbach2016) = cos cos , = sin cos , = cos sin , = cos cos , = sin cos , = cos sin , = sin sin , = cos sin , = sin cos , = sin sin , = cos sin , R R Z Z R R Z Z R R Z Z R R Z v V r n z v V r n z v V r n z v V r n z v V r n z v V r n z r n z r n z r n z r n z r n z = / , = 0,1, 2, ... = sin cos , Z m l m n r n z
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