Mathematical Physics Vol 1
Chapter 5. Series Solutions of Differential Equations. Special functions
230
Legendre polynomials
Observing the structure of coefficients a s + 2 (5.26), where s = 0 , 1 , 2 ,... , we can see that if k in the initial equation is an integer, then some of the coefficients a s + 2 can be equal to zero. For example, for k = s we have a k + 2 = a k + 4 = ··· = 0. If k is an even number, then y 1 is reduced to a polynomial of power k . If k is an odd number, then y 2 is reduced to a polynomial of power k . From (5.26) it follows that
( s + 1 )( s + 2 ) ( k − s )( k + s + 1 )
a s = −
a s + 2 , s ≤ k − 2 .
(5.28)
From this relation, all coefficients different from zero can be determined in terms of a k , namely the coefficient next to the highest power of x in the polynomial. This coefficient remains arbitrary. For convenience, it can be defined by the relation a k = 1 , k = 0 , ( 2 k ) ! 2 k ( k ! ) 2 = 1 · 3 · 5 ··· ( 2 k − 1 ) k ! , k = 1 , 2 ,... (5.29) For a k defined in this way, we obtain from (5.28)
k ( k − 1 ) 2 ( 2 k − 1 )
k ( k − 1 )( 2 k ) ! 2 ( 2 k − 1 ) 2 k ( k ! ) 2
a k
a k = −
− 2 = −
=
( 2 k − 2 ) ! 2 k ( k − 1 ) ! ( k − 2 ) !
= −
.. .
.. .
( 2 k − 2 m ) ! 2 k m ! ( k − m ) ! ( k − 2 m ) ! .
1 ) m
a k
− 2 m =( −
Definition The polynomial defined by the relation
M ∑ m = 0
( 2 k − 2 m ) ! 2 k m ! ( k − m ) ! ( k − 2 m ) !
( − 1 ) m
x k − 2 m
P k ( x )=
(5.30)
is called Legendre polynomial of power k , where M = k / 2 or ( k − 1 ) / 2 is awhole number.
This polynomial represents the solution of Legendre differential equation (5.21). Let us write down some of these polynomials
P 0 = 1;
P 1 = x
1 2
1 2
( 3 x 2 − 1 ) ;
( 5 x 3 − 3 x )
P 2 =
P
3 =
1 8 ( 35 x 4 − 30 x 2 + 3 ) ; P
1 8 ( 63 x 5 − 70 x 3 + 15 x ) .
P 4 =
5 =
Their graphs are represented in Figure 5.1.
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