Issue 48

A. Fesenko et alii, Frattura ed Integrità Strutturale, 48 (2019) 768-792; DOI: 10.3221/IGF-ESIS.48.70

T HE CONSTRUCTION OF THE MATRIX FUNDAMENTAL SOLUTION SYSTEM , THE MATRIX BASIC SOLUTION SYSTEM , THE FUNDAMENTAL MATRIX AND G REEN MATRIX FUNCTION

A

ccording to [39] the basic matrices are the solutions of the boundary matrix problems

 

 

 ( ) 0,

 Ψ δ ( )

L z Ψ

U z

(26)

j

i

j

ij

2

ij δ is Kronecker’s symbol. The basic matrices are constructed in the form

 z i Ψ Y C Y C  0 1 ( ) , ( ) z ( ) z

0,1

i

i

i

where z z Y Y are the matrix fundamental solutions of the homogeneous equation (26) correspondingly decreasing and increasing in infinity. The algorithm of fundamental solutions  ( ) z Y derivation is described in [37], where the method of fundamental matrix equation is also indicated. According to this approach, the solution is searched as the contour integral [39, 40]   ( ), ( )

   1 2 i

sz

1

( ) z

e

s ds

( )

(27)

Y

M

C

2

 1 ( ) s M , where

    2

2 s N Q P ,

  2 s

2

( ) s s M I

det ( ) s M

N

where contour C covers all poles of the matrix

,

0

  s N . Let’s calculate matrix

1

*

 s s M M M , so (27) will be transformed ( ) s ( )/ det ( )

sz

e

 C

*

( ) z

s ds

( )

1

Y

M

i

2

2

 s N 2

2

here * ( ) s M is a union matrix. With the help of the residual theorem, one derives

j

      d dz

sz

e

2

( ) j

 ( ) Re

( ) z

( ), y z y z

s

s

N

,

Y

Γ

  2 ) ( s N s N

2

(

)

j

0

 

 3 1 N e Nz ( Nz

Nz

3 1 N e

 ( ) (4 )

 ( ) (4 )

 y z

Nz

 y z

(

1),

1)

1

 2

( ) , j

j

0, 2

  4

 s N N or 2 2 4 2

i i

1

( )

( ) p s s

( ) s

s

Here, to find matrices

one uses the fact, that

,

Γ

M

Γ

4

4 p s

( )

i

0

 2

( ) , j

j

0, 2

i i

( )

4 p s

( ) s M Γ

s

( )

. Using that coefficient near the same exponents should be equal, the matrixes

are

Γ

I

i

0

found

 2 1

(2)

   (1)

(0)

 

N

,

,

P .

Γ I Γ

Q Γ

0

As a result, the fundamental matrix system is derived

 

  

1

   Nz 

z

    Nz e

*

(z)

Y

0

2 N z

1

Nz

(

)

*

776

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