PSI - Issue 81

Ivan Zvizlo et al. / Procedia Structural Integrity 81 (2026) 109–115

111

1 В j u from crack opening. So, we describe the displacement in the half-space D by Newtonian

S 0 points and the displacements potentials in the following form:

0 ( ) x

( ) x

( ) , x

, ,

D

D

B

u

u

u

D A B 



(4)

0 0

1 0

j

j

DB j

   

    

2   

x

( ) x

0 ( ) x

0 ( ) x

( ) x

D

D

D

D

u

H

H

H



30

0 0

3

3 0

j

j

j

2 x x    D j 0

2(1 )

x

x

30

(3 )0 j 

30

1 2

 

0 ( ) x

( ) , x

1,2 ,

D

D

H

H

j

D

(5)

3 0

j

2(1 )

x

x

 

30

30

D

  

  

1 2

x

  

2

( ) x

0 ( ) x

D

D

u

H

30

D

30 0

i

2(1 )

2(1 )

x

D i    x x

 

1

i

0

0 30

D i

dS

    

  

x

  

ξ

3 0 H H x ( ) , D

0 ( ) x

( ) ξ

,

D

D

u

30

20

0

j

j

0 x ξ 

2(1 ) 

x

30

D

S

0

dS

dS

 

  



ξ

ξ

( ) x

( )

( )

,

1,3 .

B

B

B

B

B

ξ D

ξ D

u

u

u

j

 

1 0

31

310

3

3 0

j

j

m

j m

x

ξ

0 m x ξ 

2

m

10

S

S

1

m

0 D j u  characterize the displacement of the interface surface S 0 points of the component D in the

Here, the unknown densities direction of the coordinate axes

0 0 j O x . The differential operators

D

3 0 ,

1, m 

B

l

have the following structure

j l

  

  

  

1 2

3 4

x

 

 

D

.

B









3 0 l

B

B

3 0

1

2

3

2

j l

j

j

j

j

2(1 )

2(1 ) 

2(1 )

x

x

x

x

x

 

 

3 0 l

2 0 l

3 0 l

1 0 l

3 0 l

B

B

B

After substituting (4) and (5) into Hooke ’ s law relation, we obtain integral representations for the stress components in the form

G

3 0   x ( ) D j

30 0    x ( ) D j DB j D

( ) , x

D

31 0

1



D

    

    

3

2

30 0   x ( ) D j

0 ( ) x

D

x

H

 

30

20

D

j

2 x x

2 x 

 

0 30

(3 )0 j

j

  

  

3

2

3 0 ( ) H x  x D j

( ) , x

1,2 ,

D

x

H

j



 

(6)

30

30 20

3 0

D

x x x

x x

x

  

 

10 20 30

10 0

0

j

 

  

x 

3

330 0    x ( ) D x

0 ( ) x

( ) , x

20 1   

D

D

H

x

H

30 20

30

3 0

i

x

1 0

i

30

i

dS

dS

 





ξ

ξ

31 0    x ( ) B j u

( )

( )

,

, .

B

B

B

B

ξ Χ

ξ Χ

u

m n k 

 

31

310

3

3 0

j

m

j m

x

ξ

0 m x ξ 

2

m

10

S

S

1

m

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