PSI - Issue 81

Taras Dubyniak et al. / Procedia Structural Integrity 81 (2026) 562–569

565

d

d

     

  

p

p





1

tg  

f

f

 



s

V

D D

s

V

, 

Q N 

N



(3)

D

D

 

  

  

Q

Q

sin 1  

cos

f f

f

f









s Q

Q

s

D

D

s

s

where  - is the force growth coefficient (determines how many times the normal pressure on the cam tooth is greater than the spring pressure). To determine the limiting moment, let us consider the equilibrium of a sliding half-coupling. Condition of equilibrium at the moment of slipping are   sin cos 0, Q V V Q f S D f       (4)

D

d d

d





Q

p





s

r

(5)

cos

sin

0,

Q

f

f R f S N tg  

M   









 

Q

r

s

o

2

2

2

2

where S , R – axial and radial reaction respectively; d s – diameter of application of the resultant friction force on the end of the half-coupling; d r – diameter of the mounting hole of the sliding half-coupling; M o – resistance moment. Having determined the force S from equation (4) and substituting it into equation (5), we determine the moment of resistance       cos sin sin cos . 2 2 2 2 2 Q p s r s r o Q s Q s r V D d d d d d M Q f f f N tg f Rf D                            (6 )

Substituting the value of Q from the equation (3) into equation (5) and introducing the corresponding variables

D

d

d

sin cos sin cos   

A B C D 



Q

s

s

1  

1  

C

f f

L

A f

f

B

f f

;

;

;

;



 

Q s

Q s

s Q

D

D

D



s

Q

Q

D

d

d

d

d

d

Q

r

r

s

r

r

,

D f

f

E f 

f

G f  

;

;

 



Q

s

s

s

V

2

2

D

D D

D

V

s

s

V

we will get





D

d

2

D

G

Q





r

,

M N L N tg  

Q         EL D

Rf

  

(7)

o

r

2

2

2

The force transmission coefficient for this coupling will be equal to