PSI - Issue 71
A. Kumar et al. / Procedia Structural Integrity 71 (2025) 453–460
456
G = Material shear modulus
By applying the Castigliano's second theorem, the shear deformation
13 4 sin F w ltG
U
13 = =
(10)
2
F
13
Shear strain
13 2 4 sin F
13 w ltG
(11)
= =
13
(12)
4 sin (
cos )
s A l =
h l −
In the direction- 1 ,
G
13
=
(13)
13
13
sin
t G G =
13
s
(14)
h
l
cos − l
Out-of-Plane Shear modulus (G 23 )
2.3.
The shear force 23 F is loaded in direction- 2 (Fig. 4(a)). As a consequence of this shear force 23 F , shear stress 23 is transmitted to both inclined and straight walls of the RCE.
Fig. 4. (a) Shear force 23 F acting on the whole structure in direction- 2 ; (b) Shear force 23 F on the RCE
If the shear force in wall AE is EA F , then
EA 2 h = l
AB F F
(15)
EA 4 F F =
, BG
The total force 23 F acting on the RCE
(16)
4 4 cos F F F = +
F +
23
EA
AB
BG
The total strain energy developed as a result of applied shear force 23 F . 2 2 2 BG EA AB w w w F F F
0
0
0
4
d 4 z +
d
d
(17)
U
z
z
=
+
2( )
2( )
2( ) A G A G
EA A G
AB
BG
According to Castigliano's second theorem, the shear deformation
( 1.5 ) h +
23 F w l
U
23 = =
(18)
2
4 (
cos )
F
tG h l −
23
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