PSI - Issue 66

Albena Doicheva et al. / Procedia Structural Integrity 66 (2024) 433–448 Author name / Structural Integrity Procedia 00 (2025) 000–000

445 13

h=25 cm

h=25 cm

10,5 11,5 12,5 13,5

13

Eurocode (H1+H2+H3)/qL 2×(Mb/jb)/qL

Eurocode (H1+H2+H3)/qL 2×(Mb/jb)/qL

12

11

10

8,5 9,5

(H1+H2+H3)/qL

(H1+H2+H3)/qL

9

h/b

1,9 2,2 2,7 3,5 4,8 7,7 20,1

h/b

1,9 2,2 2,7 3,5 4,8 7,7 20,1

a)

b)

Figure 11. Comparison of the parameters on Equation (33) calculated by Equations (22)–(24), asymmetric cross-section: ( a ) 2 1 4500kN/ cm E = . Figure 11 shows the variation in the sum with respect to the parameters of the three support reactions, 2 3 H qL H qL H qL + + , calculated by Equations (22)–(24), while the crack between the beam and the column grows. The comparison is made by Equation (33) and is shown in Table 2. 2 1 3310kN/ cm E = ; ( b ) 1

Table 2. The comparison by Equations (33) for asymmetric cross-section 25/25cm.

(

) ( s A A H H H H H H + − + + + + 1 2 3 2 s

)

γ

( ′   +  − + + ′   + + 3 j H H H 2 b b b b M M H H H j 

)

100%

1

Rd

(

)

/ h b

1

Section

100%

3

2

1

(

)

3

2

1

2.0 2.7 2.0 2.7

9.00

30.47 2.36 41.00 29.68 -2.94 44.29

E 1 = 3310 kN/cm 2

-14.49 17.79 -18.91 20.54 8.34

102.4

E 1 = 4500 kN/cm 2

102.4

Figure 12 shows the variation in the sum with respect to the parameters of the three support reactions, 2 3 H qL H qL H qL + + , calculated by Equations (15)–(17), neglecting the axial force in the expression of the potential energy of the deformation, while the crack between the beam and the column grows. The comparison is made with ( ) b b b b M j M j qL + ′ ′ and Eurocod. The comparison of the three graphs is done for h/b = 2.9. The results of Figure 12 are shown in Table 3. 1

h=25 cm

h=25 cm

15

16

Eurocode (H1+H2+H3)/qL 2×(Mb/jb)/qL

Eurocode

14

13

(H1+H2+H3)/qL

12

2×(Mb/jb)/qL

11

10

(H1+H2+H3)/qL

(H1+H2+H3)/qL

8

9

h/b

h/b

2,0 2,4 2,9 3,8 5,6 10,0 50,0

2,0 2,4 2,9 3,8 5,6 10,0 50,0

a)

b)

Figure 12. Comparison of the parameters on Equation (33), neglecting the normal force in the strain potential energy expression, calculated by Equations (15)–(17), symmetric cross-section: ( a ) 2 1 3310kN/ cm E = ; ( b ) 2 1 4500kN/ cm E = .