Issue 64
H. Zine Laabidine et alii, Frattura ed Integrità Strutturale, 64 (2023) 186-203; DOI: 10.3221/IGF-ESIS.64.12
while:
E ii is modulus of elasticity in i direction. ν ij is poison‘s ratio of orthotropic material. G ij is shear modulus in plane with normal of i and in the j direction. σ ij is normal Stress in i direction. τ ij is shear stress in plane with normal of i and in the direction of j. ε ij is strain vector. For this numerical study, a realistic parameters of the orthotropic behaviour of the timber LVL are adopted and mentioned in Tab .2 [17]:
E 11
E 22 485
E 33 280
ν 12
ν 13
ν 23
G 12 600
G 13 600
G 23
12000
0.0464
0.365
0.309
24
Table 2: Timber LVL elastic orthotropic parameters [17]. The tensile strength is 33.4 MPa, and the shear strength is 5.3 MPa [18]. For the plastic behaviour, the option “potential” was added with the following parameters:
σ
0
11 R =
(2)
σ
eq
σ σ
90
22 33 R =R =
(3)
eq
3 σ
ν
12 13 23 R =R =R =
(4)
σ
eq
while
σ 0 is the yielding strength in the direction parallel to the grain. σ 90 is the yielding stress in the direction perpendicular to the grain. σ eq is the equivalent yielding strength for isotropic behaviour, and σ eq is taken as 33.4 MPa in the present paper and it is the reference yield. In this case, it equals σ 0 [9]. The OSB plate is simulated as an isotropic material with an elastic modulus equal to 3253 MPa [19] . The concrete grade adopted is the same in the experimental program with an average density ( ρ ) of 3405 Kg/m 3 . The calculated elastic modulus depends on the concrete compressive strength (f’c) and it is given by Eqn. 5 [11]
ρ
E =(3320 f' +6900)*
(5)
c
c
2300
Its values for each TCC beam is listed in Tab. 3.
N°
Beam
f’ c (MPa)
E c (MPa)
1
A1,B1,C2
58
34413.26
2
C1, D1,F1
54.4
33560.79
3
G1
48.2
32023.63
4
B2 29490.20 Table 3: The calculated concrete elastic modulus for each TCC beam. 38.8
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