PSI - Issue 59

Andrii Pavluk et al. / Procedia Structural Integrity 59 (2024) 566–574 Andrii Pavluk et al./ Structural Integrity Procedia 00 (2019) 000 – 000

571

6

1  0 z

1  0 z

1  0 z

3

1

1

1

z

2 ( ) M fuzdA fuzbdz b E z k     ( ) (

2 3 ( ) )

( z dz b E 

1

с

1

1

1

2

c

с

с

с

с

с

с

3

4 2 1 z

1 ( )

),

k

с

2

4

(18)

z

z

z

1

1

2

2

2

2 E z k  (

2 3 ( ) ) ( 

( ) M fuzdA fuz fbdz    ( ) ( )

)  

1 z a z a dz z 2 4 1 с с

2

1

1

2

c

с

с

с

с

z

z

z

1

1

1

z

1

1

1

1

2

3 E a z E z a k   2 (

2

4 a z k 

2

3 a z dz E a  )

( )

( )

2

с

1

2

2

1

2

2

1

с

с

с

с

с

с

с

4

z

1

3

5

4

4

3

1

1

1

1

1

z

z

z

z

z

2

2

( )

( )

a

E a

k

a

k

a

E a

E

2

2

2

1

1

с

с

с

с

с

2

2

1

2

2

1

2

с

с

с

3

3

5

4

4

5

4

1

1

z

z

2

2

( )

( )

.

k

1 a k  с

a

1

с

2

1

2

2

5

4

(19) By substituting formulas (18) and (19) into equation (17), we obtain:

3

4

4

3

5

1

1

1

1

1

z

z

z

z

z

2

2

( M b E 

( )

)

( )

1 k

E a

E a

k

a

1

1

2

2

2

с

с

с

с

с

2

1

2

2

1

c

с

с

с

3

4

4

3

5

z 

a 

4

4

3

5

4

1

1

1

1

z

z

z

z

2

2

2

( )

( )

( )

.

k

a

1 E a E a  с

k

1 a k  с

2

1

1

с

с

с

2

2

1

2

2

1

2

2

с

с

4

4

3

5

4

(20) The bending moment from the neutral axis for the tensile zone in the normal cross-section is equal to:

,

1 t t M M M   t

2

(21)

z

z

z

3

1 z M f udA f ubzdz E zbdz E b          1 1 2 1 2 2 1 1 ( ) ( ) t t t t t

,

1

t

3

0

0

0

(22)

z

z

z

1

2

2

2

2

1 M fuzdA fuz fbdz E z az adz z z z E az E azdzEa E a              1 1 2 2 2 2 1 2 4 3 4 3 2 2 2 ( ) ( ) ( ) ( ) 1 1 1 1 1 ( ) t t t t t t z z z z t t t

3

1

z

.

1 E a E a 

1

t

1

2

1

2

1

2

t

t

t

t

t

t

t

4

3

4

3

z

1

(23) By substituting formulas (22) and (23) into equation (21), we obtain:

3

4

3

4

3

1

1

1

1

1

z

z

z

z

z

.

1 M E b E a E a    2 t t

1 E a E a  t

2

1

t

t

1

2

1

2

t

t

t

t

t

t

3

4

3

4

3

(24) By substituting formulas (24) and (20) into equation (7), we obtain:

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