PSI - Issue 51
Victor Rizov et al. / Procedia Structural Integrity 51 (2023) 206–212 V. Rizov / Structural Integrity Procedia 00 (2022) 000–000
210
5
2 h
2 h
2 h
y
y
y
1 i 1 1 i 1 1 y i n i
1 i 2 1 i 2 2 y i n i
1 i 3 1 i 3 y i n i
1 1 1 z dy dz i
2 2 2 z dy dz ri
3 3 3 z dy dz ui
,
(9)
2 h
2 h
2 h
i y 2 , 2 1 i y ,
i y 3 and 3 1 i y are the
where 2 n and n are the number of layers, ri and ui are the normal stresses,
coordinates, 2 y , 2 z , 3 y and 3 z are the centroidal axes. The stress, i , is obtained by (2). The strain that is ri by replacing of with r . The strain, r , is found by replacing 1 and 1 z with 2 and 2 z in (7). The stress ui is obtained by replacing with u in (2) where u is found by replacing 1 and 1 z with 3 and 3 z in (7). Further two equations are written by expressing the rotations of the two delamination arms by integrals of Maxwell Mohr a l a 3 1 1 , a l a 3 2 2 . (10) The equation for equilibrium of the bending moments and equations (10) are used to determine 1 , 2 and 3 . Formula (5) is applied also to obtain TDSE cumulated in the left-hand delamination arm by performing the necessary replacements. Here, the time-dependent SE density, i u 02 , is found by replacing of i and with ri and r in (6). The TDSE is obtained by replacing 1 n , i y 1 , 1 1 i y , i u 01 and 1 z with n , i y 3 , 3 1 i y , i u 03 and 3 z in (5). The time-dependent SE density, i u 03 , is derived by using (6). By substituting the time-dependent SE, 1 U , 2 U and 3 U , in (4) and then in (3), one obtains involved in (2) is expressed by (7). The relationship (2) is used also to obtain
2 h
h
h
2 1 2 2 2 2 y y i n i i i
y
2 1 3 1 3 y y i n i i i
1 i 1 1 i 1 1 y i n i
1 h
2 2 u dy dz i 02
3 3 u dy dz i 03
G
1 1 u dy dz i 01
.
(11)
2 h
2 h
2 h
The MatLab is used to solve (11). The TDSERR for the delamination in Fig. 1 is found also by considering the compliance. For this purpose, beam compliances, 1 C and 2 C , are written as
1
2
C
C
,
,
(12)
1
2
M
M
1
2
1 M and
1 M are obtained as
where
2 h
2 h
y
y
1 i 1 1 i 1 1 i y i n i
1 i 2 1 i 2 2 y i n i
M
z dy dz
M
z dy dz
.
(13)
1
1 1 1
2
2 2 2
ri
2 h
2 h
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