Issue 35
G. Meneghetti et alii, Frattura ed Integrità Strutturale, 35 (2016) 172-181; DOI: 10.3221/IGF-ESIS.35.20
significantly higher in Fig. 4b than in Fig. 4a. To evaluate the first derivative at r=R (Eq. (6)), the temperature-distance data along the seven considered paths were fitted using a proper polynomial function, shown with a continuous line in Fig. 4.
293 293.2 293.4 293.6 293.8 294 294.2 294.4
(a)
315 316 317 318 319 320 321 322
(b)
=0° R=3·10 -4 m f L =35 Hz K=60 MPa ·m 0.5
= 0° R=3·10 -4 m f L =37 Hz K=26 MPa·m 0.5
r T
r T
Rr
Rr
T m [K]
T m [K]
r=R
r=R
0
5.0·10 -4
1·10 -3
1.5·10 -3
2.0·10 -3
2.5·10 -3
0
5.0·10 -4
1·10 -3
1.5·10 -3
2.0·10 -3
2.5·10 -3
r [m]
r [m]
Figure 4 : Typical radial temperature profiles measured during the tension-compression fatigue tests in the case of (a) K=26 MPa·m 0.5 and (b) K =60 MPa·m 0.5 .
E NERGY PER CYCLE AVERAGED IN A VOLUME AT THE CRACK TIP
F
ig. 5a, 5b and 5c show the specific thermal flux h at the different points along the boundary of V (Fig. 1) for specimen V_3, V_4 and V_5, respectively, using =16 W/(m·K) [8]. Finally, Fig. 5d shows, as an example, the specific energy flux per cycle q , obtained simply dividing h by the load test frequency. In the authors’ opinion, for the material and the experimental conditions analysed in the present paper, a reasonably accurate evaluation of the heat power can be achieved by considering K values higher than 25 MPa·m 0.5 (K max >12.5 MPa·m 0.5 ). Having in hand the specific thermal flux h evaluated at different angles of the boundary of V, numerical integration was performed according to Eq. (6). To evaluate the errors due to the discretisation, Eq. (6) was solved by dividing the 360° angle starting from a minimum of 4 intervals ( =90°) to a maximum of 24 ( =15°). A 0.51% variation on results was found by using 8 as compared to 24 intervals. Therefore, 8 intervals ( =45°) were adopted in numerical calculations. Finally, the energy per cycle averaged in the volume V, Q*, was evaluated by means of Eq. (7b). Results are listed in Tab. 1 and it can be seen that Q* increases as K increases. It should be noted that K are elastically calculated, independently on plastic zone size evaluations.
V_3 specimen K [MPa·m 0.5 ] Q* [MJ/m 3 cycle] 26.3 0.813 26.8 0.504 28.4 0.655 31.2 0.727 35.6 0.829 45.2 1.02 49.6 1.32 55.3 1.33 64.1 3.28
V_4 specimen K [MPa·m 0.5 ] Q* [MJ/m 3 cycle] 31.5 1.21 36.7 1.47 42.0 1.55 78.7 4.64 98.0 5.19
V_5 specimen K [MPa·m 0.5 ] Q* [MJ/m 3 cycle] 28.5 0.581 30.3 1.80 32.9 1.91 36.9 2.18 40.6 1.93 45.7 2.60 53.2 2.99 60.1 4.00 66.9 5.96
Table 1 : Q* values calculated for different specimens at different K values.
177
Made with FlippingBook Ebook Creator