Issue 29
M. Marino, Frattura ed Integrità Strutturale, 29 (2014) 96-110; DOI: 10.3221/IGF-ESIS.29.10
• [0, ) d t t . At each step, it results
.
i d
= e d de
2 3 = = 0 d d
= E de
=0
and thereby Eq. (12) gives
,
,
d
1
Hence, from Eq. (13-15) and (16), it results = = in β β β . • = d t t . It results = d and = > d d
, and thereby Eq. (13-15) and (16) give (since 2 = 0 )
= / de
= / = / de de
1
1
1 2 3
d
/ ( , , ) = / e e β
D
D
D
(19)
2
2
d
= / de
r
D
D
D
0
3
d
= 0
= 0
Accordingly, it results =(1 / , / , 0) t D D de de C β (see Fig. 4). Thereby, stress d and the corresponding strain d denote reference stress and strain values at the onset of the direct transformation. Moreover, from Eq. (12) and since 2 3 = = 0 d d , it results =0 i d , = e d de , and 1 = = d t E de . Accordingly, 1 = d d t E de and = d d t de are the starting stress and the starting strain of the direct transformation, respectively. • [ , ) d d t end t t t . At each step, it results 2 > 0 d and 3 = 0 d , and thereby Eq. (12) gives = i d de , =0 e d , and = = d t . Accordingly, a plateau in the stress-strain response is obtained during the martensitic orientation that occurs at the direct transformation stress d t (see Fig. 3). During the overall transformation, the evolution laws for the volume fractions result in 1 2 = = / D e as long as 2 <1 (and thereby 1 > 0 ). Accordingly, a complete direct martensitic transformation (corresponding to 2 going from 0 to 1) is obtained in the time interval d t (see Fig. 4). Thereby, time = = d d end end t t dt t corresponds to 2 =1 and 1 = 0 (but 2 > 0 d and 3 = 0 d ), or, in other words, to a complete direct transformation. In this situation and as shown in Fig. 4, variations of tentative volume fractions are the same as in Eq. (19), and Eq. (16) gives / 0 = 1 / = = 1 0 0 D pr D de de C β β β β (20) and ( ) = t β β
, with the strain produced during the martensitic lattice orientation being fully
Moreover, actual strain is = d t
D
(see Fig. 3).
i
=
inelastic, and equal to
D
1 [ , ] d end
t t t . At each step, alloy composition is governed by the projection described in Eq. (20). It results
•
2 = ( d t
d
= e d de
i d
2 3 = = 0 d d
E
= 0
)
, and thereby Eq. (12) gives
,
, and
(see Fig. 3).
D t
= d de ). Consider
1 1 [ , 2 ] t t , the material element undergoes unloading conditions (in fact,
Traction unloading. For
the following relevant stress and strain values:
r
r
d
r
r
r
2 E de 1 d d
2 E de
E de E de
=
=
=
,
=
max
1
E
2
1 ( r
2 = ( d t E
d
d
) E E de
=
)
with
and
. Moreover, let introduce the time interval
max
max
D t
2
e
= / r R
t
and the time values:
r
= , r t
dt t
= , t t r r
r
r
r
r
r
r
(21)
t
t
t
t
t
=
,
=
max
t
end
end
t
e
< 2 r end
t
t is assumed. Model predictions are as follows:
where
1
1 ( , ) r t t t . At each step, it results
2 d , from r
i d
e
de ,
2 3 = = 0 d d
= E de
d
=0
=
•
, and thereby Eq. (12) gives
,
, volume fractions follow Eq. (20). Otherwise, if
. Accordingly, it results = =(0,1, 0) t β β . In fact, if > d
1 3 = = = 0 d d d . 2
Eq. (13-15) it results
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