Fatigue Crack Paths 2003

0.1

0.1

1.50

2.5

18

ρd=

(c)

(b)

(a)

0.1

ρd =

0.4

16

ξ =

0.5 1.0 12 0

ξ =

α0.0

α 01.46802

α 01.0246802

/

0.2

0.4

1246802

0.6

0.02

0.8

K

1.0

K=01* .57020505

ρξd=0..8 1

14

1.2

0

ξ=0.4

α

(e)

(d)

(f)

1.5 2.05

0.0.2

ρd =

ρd =

/

12468

ξ=0.1

α 0.02

0.4

0.6

α 0.0

1.0

01.8460

10

0.8

0.24

468

K

1.0

0.68

K=01* .7025 5050

ρd=

1.2

2

ξ = 0.8

0

0.00

0.25

0.50

0.75

1.00

0.5

0.00

0.25 N O R M A L I ZCEODO R D I N A TζE*,=ζ / h 0.50 0.75

1.00

1.02

0.5

0.00

0.25 N O R M A L I ZCEODO R D I N A TζE*,=ζ/ h 0.50 0.75

1.00

N O R M A L I ZCEODO R D I N A TζE*,=ζ/ h

1.2

,F*IK along the crack front (*ζ ), for different values of α :

Figure 2. Dimensionless SIF

(unnotched bar) (

( = 1.0 ξ (a),

= 4.0 ξ (b),

= 8.0 ξ (c));

= 1.0 ξ (d),

= 83.2 t K

00.1= t K

= 4.0 ξ

= 8.0 ξ

(e),

(f)).

56

(a)

(b)

(c)

ρξd = 0.41

ρξd = 0.81

ρξd = 0.1

1.50

/

1.25

1.25

α

0.0.2

0.50

01.0257005050

1.2

4

0.0205 1 700

1.01.2

0.4

α

α

0.0

0.024

0.2

0.6

123

0.46

0.8

01.680

K*=K1.50

0.8

1.0

1.2

0

6

(e)

(d)

(f)

ρ d ξ==0.1

ρ

d = ξ=0.8

ρ

=

1.025050

1.025050

d

ξ=0.4

α

45

0.0.2

α

0.4

0.0 0.20.46 0.8

α0.0.20.40.60.81.01.2

/

0.75

0.5705

0.6

3

=K

0.50

0.8

2

K *

1

1.2

0.00

0.25

0.50

0.75

1.00

0.025

0.00

0.25 N O R M A L I ZCEODO R D I N A T ζE *,=ζ/ h 0.50 0.75

1.00

0.025

0.00

0.25 N O R M A L I Z ECODORDINATEζ ,*= ζ/h 0.50 0.75

1.00

1.02

N O R N A L I Z ECDO O R D I N A T Eζ *,= ζ/h

1.0

along the crack front (*ζ ), for different values of α :

Figure 3. Dimensionless SIF

,M*IK

(unnotched bar) (

( = 1.0 ξ (a),

= 4.0 ξ (b),

= 8.0 ξ (c));

= 1.0 ξ (d),

00.1= t K

= 83.2 t K

= 4.0 ξ

= 8.0 ξ

(e),

(f)).